A.2 Derivative of Exponential Functions

On this screen we're going to use Desmos to examine the derivative of exponential functions like 2๐‘ฅ, 3.25๐‘ฅ, and such.

Exploration of the derivative of ๐‘Ž๐‘ฅ

Let's use Desmos to examine the derivative of ๐‘Ž๐‘ฅ for various values of ๐‘Ž.

Exploration 1

[End Exploration 1]

Let's see how the discovery we made in Exploration 1 follows from the definition of the derivative as applied to the exponential function ๐‘“(๐‘ฅ) =๐‘Ž๐‘ฅ. Recall the definition of the derivative:

๐‘“โ€ฒ(๐‘ฅ)=limโ„Žโ†’0๐‘“(๐‘ฅ+โ„Ž)โˆ’๐‘“(๐‘ฅ)โ„Ž We are considering ๐‘“(๐‘ฅ) =๐‘Ž๐‘ฅ, so ๐‘“(๐‘Ž +โ„Ž) =๐‘ฅ๐‘ฅ+โ„Ž. Making these substitutions in the derivative definition then gives us ๐‘“โ€ฒ(๐‘ฅ)=๐‘‘๐‘‘๐‘ฅ๐‘Ž๐‘ฅ=limโ„Žโ†’0๐‘Ž๐‘ฅ+โ„Žโˆ’๐‘Ž๐‘ฅโ„Ž=limโ„Žโ†’0๐‘Ž๐‘ฅ๐‘Žโ„Žโˆ’๐‘Ž๐‘ฅโ„Ž=limโ„Žโ†’0๐‘Ž๐‘ฅ(๐‘Žโ„Žโˆ’1)โ„Ž[๐‘Ž๐‘ฅ is unaffected by the limit]=๐‘Ž๐‘ฅlimโ„Žโ†’0๐‘Žโ„Žโˆ’1โ„Ž

The preceding equation, combined with the discussion in Exploration 1, provides one way to define the number e:

Definition of e

e is defined to be the number such that

limโ„Žโ†’0๐‘’โ„Žโˆ’1โ„Ž=1

To five digits, this number is ๐‘’ =2.71828.

With this definition of e in place, we have the key result we discovered in Exploration 1:

Derivative of ๐‘’๐‘ฅ

๐‘‘๐‘‘๐‘ฅ๐‘’๐‘ฅ=๐‘’๐‘ฅ

We all love this particular derivative, since it's so easy to remember!

One reason e appears so often in describing physical phenomena

More importantly, this result is the first indication of why the number e appears so often when we describe physical phenomena: The rate of change of the function ๐‘“(๐‘ฅ) =๐ถ๐‘’๐‘ฅ is proportional to the value of the function itself. For instance, the way that bacterial growth occurs is that each bacterial cell subdivides so 1 becomes 2, and 2 become 4, and so on. That means that the rate at which they multiply at a given moment, ๐‘‘๐‘๐‘‘๐‘ก, is directly proportional to how many are present at that time, ๐‘(๐‘ก): they grow at twice the rate when there are 2 present as when there are 1, and four times the rate when there are 4 present instead of 1, and sixteen times the rate when there are 16 present than when there is 1. That is, ๐‘‘๐‘๐‘‘๐‘ก =๐‘˜๐‘(๐‘ก), where the constant k depends on the particular type of bacteria and how quickly they subdivide. This direct proportionality between ๐‘‘๐‘๐‘‘๐‘ก and ๐‘(๐‘ก) leads straight to the bacterial growth equation ๐‘(๐‘ก) =๐‘0๐‘’๐‘˜๐‘ก. We'll explore this and related ideas in much more depth later. For now, you might choose to marvel at how this number e has the remarkable property that ๐‘‘๐‘‘๐‘ฅ๐ถ๐‘’๐‘ฅ =๐ถ๐‘’๐‘ฅ.

Derivative of ๐‘Ž๐‘ฅ for other values of ๐‘Ž

For completeness, here is a result that we'll be able to prove easily in a few screens. For now, we state the result and provide a more cumbersome proof in the Show/Hide box immediately below.

Derivative of ๐‘Ž๐‘ฅ

For any value of ๐‘Ž >0 : ๐‘‘๐‘‘๐‘ฅ๐‘Ž๐‘ฅ=๐‘Ž๐‘ฅโ‹…lnโก๐‘Ž

This result matches what we saw in Exploration 1 above: the function ๐‘“(๐‘ฅ) =๐‘Ž๐‘ฅ and its derivative have the same-shaped curve because they differ only by the (constant) factor lnโก๐‘Ž. And since lnโก๐‘’ =1, when ๐‘Ž =๐‘’ the function ๐‘“(๐‘ฅ) =๐‘’๐‘ฅ and its derivative are identical.

The Desmos calculator below let's you examine the function ๐‘“(๐‘ฅ) =๐‘Ž๐‘ฅ (solid curve) and its derivative ๐‘“โ€ฒ(๐‘ฅ) =๐‘Ž๐‘ฅ โ‹…lnโก๐‘Ž (dashed curve) on the same plot, as we did in Exploration 1. Now there is a slider beneath the graph that lets you see what happens for various values of a.

Practice Problems for the derivative of exponential functions

Practice Problem 1

Consider the function ๐‘“(๐‘ฅ) =8๐‘ฅ. Then ๐‘“โ€ฒ(๐‘ฅ) =

(A) 8๐‘ฅ(B) 7๐‘ฅ(C) 8๐‘ฅโ‹…lnโก8(D) 8๐‘ฅโˆ’1(E) none of these 

Practice Problem 2

Consider the function ๐‘“(๐‘ฅ) =๐‘’๐‘ฅ. Then ๐‘‘๐‘“๐‘‘๐‘ฅ =

(A) ๐‘’(B) ๐‘’๐‘ฅ(C) ๐‘’๐‘ฅโˆ’1(D) (๐‘’โˆ’1)๐‘ฅ(E) none of these

Practice Problem 3

An equation for the tangent line to the curve ๐‘ฆ =๐‘’๐‘ฅ at ๐‘ฅ =2 is

(A) ๐‘ฆโˆ’๐‘’2=๐‘’2(๐‘ฅโˆ’2)(B) ๐‘ฆโˆ’๐‘’=๐‘’(๐‘ฅโˆ’2)(C) ๐‘ฆโˆ’2=๐‘’2(๐‘ฅโˆ’๐‘’2)(D) ๐‘ฆ+๐‘’2=๐‘’2(๐‘ฅ+2)(E) none of these
View/Hide Solution

Step 1. Find the ๐‘ฆ-value of the point of interest: ๐‘ฆ0 =๐‘“(๐‘Ž).

We're interested in the point ๐‘ฅ =2, so have ๐‘ฅ0 =๐‘Ž =2. Since ๐‘ฆ =๐‘“(๐‘ฅ) =๐‘’๐‘ฅ,

๐‘ฆ0=๐‘“(2)=๐‘’2

Hence we're looking for the tangent line to the curve at the point (2,๐‘’2). โ—‚

Step 2. Find the value of the derivative at the point of interest, ๐‘“โ€ฒ(๐‘Ž).

Since ๐‘“(๐‘ฅ) =๐‘’๐‘ฅ,

๐‘“โ€ฒ(๐‘ฅ)=๐‘’๐‘ฅ

Hence

๐‘“โ€ฒ(2)=๐‘’2โ—‚

Step 3. Use these two pieces of information to write the equation of the tangent line. (See the Show/Hide box above for more information about this step.)

The equation of the tangent line to a curve is given by

๐‘ฆโˆ’๐‘“(๐‘Ž)=๐‘“โ€ฒ(๐‘Ž)(๐‘ฅโˆ’๐‘Ž)

Using the information we found above, then, we have

๐‘ฆโˆ’๐‘’2=๐‘’2(๐‘ฅโˆ’2)โŸน(A)โœ“
Graph showing the function f(x) = e^x, and the tangent line to its curve at x=2, which has slope equal to the derivative of the exponential function.

[close solution]

Practice Problem 4

Consider the function ๐‘“(๐‘ฅ) =3๐‘ฅ. You know that ๐‘“(2) =32 =9.

Use a linear approximation to estimate the value of 32.01.

(A) 9+3lnโก3(B) 2+0.09lnโก3(C) 0.09lnโก3 (D) 9+0.09lnโก3(E) none of these
View/Hide Solution

Our solution requires the rate at which the function ๐‘“(๐‘ฅ) =3๐‘ฅ changes at ๐‘ฅ =2. That rate is, of course, the derivative's value at ๐‘ฅ =2:

๐‘“(๐‘ฅ)=3๐‘ฅ๐‘“โ€ฒ(๐‘ฅ)=3๐‘ฅโ‹…lnโก3๐‘“โ€ฒ(2)=32โ‹…lnโก3=9lnโก3โ—‚

We can then use that rate

value at 2+๐‘‘๐‘ฅโž๐‘“(2+๐‘‘๐‘ฅ)โ‰ˆ๐‘“ value at 2โž๐‘“(2)+(rate at ๐‘ฅ=2)โ‹…(๐‘‘๐‘ฅ)โžยฏยฏยฏโžยฏยฏยฏโžsmall change ๐‘‘๐‘“๐‘“(2+0.01)โ‰ˆ9+(9lnโก3)โ‹…(0.01)โ‰ˆ9+0.09lnโก3โŸน (D)โœ“

Using a calculator we find that our approximation is, to four decimal places, 32.01 โ‰ˆ9 +0.09lnโก3 =9.0989.
For comparison purposes, the actual value, to four decimal places, is 32.01 =9.0994.

[close solution]

What questions or thoughts do you have about the material on this screen, or any other Calculus-related item? How are these problems: easy? challenging? Please let the Community know on our Forum!


The Upshot

  1. The easiest derivative of all to remember: ๐‘‘๐‘‘๐‘ฅ๐‘’๐‘ฅ =๐‘’๐‘ฅ.
  2. Almost as easy: ๐‘‘๐‘‘๐‘ฅ๐‘Ž๐‘ฅ =๐‘Ž๐‘ฅ โ‹…lnโก๐‘Ž

On the next screen , we'll add the derivatives of two trig functions to our repertoire: ๐‘‘๐‘‘๐‘ฅsinโก๐‘ฅ and ๐‘‘๐‘‘๐‘ฅcosโก๐‘ฅ.