On this screen we're going to use Desmos to examine the derivative of exponential functions like 2๐ฅ,3.25๐ฅ, and such.
Exploration of the derivative of ๐๐ฅ
Let's use Desmos to examine the derivative of ๐๐ฅ for various values of ๐.
Exploration 1
[End Exploration 1]
Let's see how the discovery we made in Exploration 1 follows from the definition of the derivative as applied to the exponential function ๐(๐ฅ)=๐๐ฅ. Recall the definition of the derivative:
๐โฒ(๐ฅ)=limโโ0๐(๐ฅ+โ)โ๐(๐ฅ)โ We are considering ๐(๐ฅ)=๐๐ฅ, so ๐(๐+โ)=๐ฅ๐ฅ+โ. Making these substitutions in the derivative definition then gives us ๐โฒ(๐ฅ)=๐๐๐ฅ๐๐ฅ=limโโ0๐๐ฅ+โโ๐๐ฅโ=limโโ0๐๐ฅ๐โโ๐๐ฅโ=limโโ0๐๐ฅ(๐โโ1)โ[๐๐ฅisunaffectedbythelimit]=๐๐ฅlimโโ0๐โโ1โ
The preceding equation, combined with the discussion in Exploration 1, provides one way to define the number e:
Definition of e
e is defined to be the number such that
limโโ0๐โโ1โ=1
To five digits, this number is ๐=2.71828.
The calculator below plots ๐โโ1โ versus h,
so you can see visually what the values are as limโโ0.
Use the slider beneath the calculator to change the value of a: you'll find that for ๐=๐โ2.72, the limit as โโ0 equals 1.
With this definition of e in place, we have the key result we discovered in Exploration 1:
Derivative of ๐๐ฅ
๐๐๐ฅ๐๐ฅ=๐๐ฅ
We all love this particular derivative, since it's so easy to remember!
One reason e appears so often in describing physical phenomena
More importantly, this result is the first indication of why the number e appears so often when we describe physical phenomena: The rate of change of the function ๐(๐ฅ)=๐ถ๐๐ฅ is proportional to the value of the function itself. For instance, the way that bacterial growth occurs is that each bacterial cell subdivides so 1 becomes 2, and 2 become 4, and so on. That means that the rate at which they multiply at a given moment, ๐๐๐๐ก, is directly proportional to how many are present at that time, ๐(๐ก): they grow at twice the rate when there are 2 present as when there are 1, and four times the rate when there are 4 present instead of 1, and sixteen times the rate when there are 16 present than when there is 1. That is, ๐๐๐๐ก=๐๐(๐ก), where the constant k depends on the particular type of bacteria and how quickly they subdivide. This direct proportionality between ๐๐๐๐ก
and ๐(๐ก) leads straight to the bacterial growth equation ๐(๐ก)=๐0๐๐๐ก. We'll explore this and related ideas in much more depth later. For now, you might choose to marvel at how this number e has the remarkable property that ๐๐๐ฅ๐ถ๐๐ฅ=๐ถ๐๐ฅ.
Derivative of ๐๐ฅ for other values of ๐
For completeness, here is a result that we'll be able to prove easily in a few screens. For now, we state the result and provide a more cumbersome proof in the Show/Hide box immediately below.
Derivative of ๐๐ฅ
For any value of ๐>0:๐๐๐ฅ๐๐ฅ=๐๐ฅโ lnโก๐
We'll be able to develop this result quite easily once we have the "Chain Rule" tool in our repertoire
a few screens from now. In the meantime:
The first few lines duplicate what we did above, since we once again start with the definition of the derivative applied to the function ๐(๐ฅ)=๐๐ฅ.
This result matches what we saw in Exploration 1 above: the function ๐(๐ฅ)=๐๐ฅ and its derivative have the same-shaped curve because they differ only by the (constant) factor lnโก๐. And since lnโก๐=1, when ๐=๐ the function ๐(๐ฅ)=๐๐ฅ and its derivative are identical.
The Desmos calculator below let's you examine the function ๐(๐ฅ)=๐๐ฅ (solid curve) and its derivative ๐โฒ(๐ฅ)=๐๐ฅโ lnโก๐ (dashed curve) on the same plot, as we did in Exploration 1. Now there is a slider beneath the graph that lets you see what happens for various values of a.
Practice Problems for the derivative of exponential functions
Practice Problem 1
Consider the function ๐(๐ฅ)=8๐ฅ. Then ๐โฒ(๐ฅ)=
We found above that when ๐(๐ฅ)=๐๐ฅ,๐โฒ(๐ฅ)=๐๐ฅโ lnโก๐.
Hence given ๐(๐ฅ)=8๐ฅ,๐โฒ(๐ฅ)=8๐ฅโ lnโก8โน(C)โ
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Savingโฆ
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This is one you will quickly remember:
๐๐๐ฅ๐๐ฅ=๐๐ฅโน(B)โ
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Find the ๐ฆ-value of the point of interest: ๐ฆ0=๐(๐).
Find the value of the derivative at the point of interest, ๐โฒ(๐).
Use these two pieces of information, ๐tangent=๐โฒ(๐), and the point of interest (๐ฅ0,๐ฆ0), to write the equation of the tangent line in Point-Slope form:
Tangent Line to a Curve:๐ฆโ๐ฆ0=๐tangent(๐ฅโ๐ฅ0)๐ฆโ๐(๐)=๐โฒ(๐)(๐ฅโ๐)
Step 1. Find the ๐ฆ-value of the point of interest: ๐ฆ0=๐(๐).
We're interested in the point ๐ฅ=2, so have ๐ฅ0=๐=2. Since ๐ฆ=๐(๐ฅ)=๐๐ฅ,
๐ฆ0=๐(2)=๐2
Hence we're looking for the tangent line to the curve at the point (2,๐2).โ
Step 2. Find the value of the derivative at the point of interest, ๐โฒ(๐).
Since ๐(๐ฅ)=๐๐ฅ,
๐โฒ(๐ฅ)=๐๐ฅ
Hence
๐โฒ(2)=๐2โ
Step 3. Use these two pieces of information to write the equation of the tangent line. (See the Show/Hide box above for more information about this step.)
The equation of the tangent line to a curve is given by
๐ฆโ๐(๐)=๐โฒ(๐)(๐ฅโ๐)
Using the information we found above, then, we have
๐ฆโ๐2=๐2(๐ฅโ2)โน(A)โ
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Using a calculator we find that our approximation is, to four decimal places, 32.01โ9+0.09lnโก3=9.0989.
For comparison purposes, the actual value, to four decimal places, is 32.01=9.0994.
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What questions or thoughts do you have about the material on this screen, or any other Calculus-related item? How are these problems: easy? challenging? Please let the Community know on our Forum!
The Upshot
The easiest derivative of all to remember: ๐๐๐ฅ๐๐ฅ=๐๐ฅ.
Almost as easy: ๐๐๐ฅ๐๐ฅ=๐๐ฅโ lnโก๐
On the
next screen
, we'll add the derivatives of two trig functions to our repertoire: ๐๐๐ฅsinโก๐ฅ and ๐๐๐ฅcosโก๐ฅ.
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